Asked by Eagertolearn
1. A solution containing 0.100 mol of Na2CO3 and 0.100 mol of NiCl2 is allowed to react. Which reactant is the limiting reactant?
2. A solution containing 0.100 mol of Na2CO3 and 0.100 mol of NiCl2 is allowed to react. How many moles of precipitate form in this reaction?
2. A solution containing 0.100 mol of Na2CO3 and 0.100 mol of NiCl2 is allowed to react. How many moles of precipitate form in this reaction?
Answers
Answered by
DrBob222
Limiting reagent problems are worked as a special case of regular stoichiometry problems. Here are two example problems, both worked completely. Just follow the steps.
If you have trouble, post your work ad explain in detail the trouble you are having and I'll be happy to help you through it.
stoichiometry problem here.
http://www.jiskha.com/science/chemistry/stoichiometry.html
limiting reagent problem here.
http://www.jiskha.com/science/chemistry/limiting_reagent_problem.html
If you have trouble, post your work ad explain in detail the trouble you are having and I'll be happy to help you through it.
stoichiometry problem here.
http://www.jiskha.com/science/chemistry/stoichiometry.html
limiting reagent problem here.
http://www.jiskha.com/science/chemistry/limiting_reagent_problem.html
Answered by
Eagertolearn
Can you explain how I get the moles and I should be able to do it from there.
Answered by
DrBob222
Both problems give you the mols to start.
You CONVERT mols of what you are given to mols of the product by using the coefficients in the balanced equation. For example,
Na2CO3 + NiCl2 ==> NiCO3 + 2NaCl
You have 0.1 mol Na2CO3. How many mols NiCO3 will it form if you have 0.1 mo Na2CO3 and all of the NiCl2 you need. You will obtain 01 mol Na2CO3 x (1 mol NiCO3/1 mol Na2CO3) = 0.1 mol x (1/1) = 0.1 mol NiCO3.
You CONVERT mols of what you are given to mols of the product by using the coefficients in the balanced equation. For example,
Na2CO3 + NiCl2 ==> NiCO3 + 2NaCl
You have 0.1 mol Na2CO3. How many mols NiCO3 will it form if you have 0.1 mo Na2CO3 and all of the NiCl2 you need. You will obtain 01 mol Na2CO3 x (1 mol NiCO3/1 mol Na2CO3) = 0.1 mol x (1/1) = 0.1 mol NiCO3.
Answered by
Eagertolearn
Thank You that really helped
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