Apparently you have a circle of radius 6 inside a square of side 12
Do't know what was shaded, but just find the area of (part of?) the circle, and the area of (part of?) the square. Then subtract as needed
find the area of the shaded region in the figure assuming the quadrilateral inside the circle is a square.
x^2+y^2=36
(the picture is of a square inside a circle on a coordinate plane)
3 answers
the shaded part isthe outside of the square. so how would i find that part?
sorry - misread the question. If the square is inside the circle of radius 6, then the diagonal of the square is a diameter of the circle.
That means the diagonal of the square is 12, and the sides are 6√2. The area of the square is thus 72.
So, now you know the area of the circle and the area of the square.
That means the diagonal of the square is 12, and the sides are 6√2. The area of the square is thus 72.
So, now you know the area of the circle and the area of the square.
1 answer