The secant is negative in QII and QIII
104° = 180° - 76°
The other answer is 180°+76° = 256°
Always draw the triangles in the various quadrants for this kind of problem.
Since secant is h/x, where h is the hypotenuse, if x is negative sec is negative. That happens in QII and QIII.
Determine two angles between 0°and 360°that have a secant of -4. Round your answers to the nearest degree.
There are tw answer 104°( I got this one but there is also 256° I don't have anyidea for this one please explain to me
I appreciate your time thankyou sooo much!!!
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