Asked by Nelly
F(x) = (x^3 - x + 1)^4
f'(x)=
f'(x)=
Answers
Answered by
Steve
Just use the chain rule
d/dx (u^n) = n u^(n-1) du/dx
so, we get
4 (x^3-x+1)^3 * (3x^2-1)
d/dx (u^n) = n u^(n-1) du/dx
so, we get
4 (x^3-x+1)^3 * (3x^2-1)
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