f=(x)cosh^(-1)((x)/(2))-√((x)^(2)-4) f'=

Evaluate integral e^3x cosh 2x dx. A.1/2 e^5x + 1/2 e^x + C B.1/10 e^5x + 1/2e^x + C<<< my answe...

Let y(x)=ln(cosh(x)+ sqrt(cosh^2(x)−1)) Find the derivative Dxy= I don't know what to do with...

find f' of f=(x)cosh^(-1)((x)/(2))-√((x)^(2)-4)

what is x and cosh ln(x) when tanh(lnx^(1/2)= 12/13

How to derive cosh (3x) in terms of cosh (x) and sinh (x) ? Initially I start with 1/2 (e^3x+e^-3x)...

how do I solve cosh((1+j)/2) to form of a+jb????

Evaluate: (b) cosh(π) (c) cos(iπ)

Sinh x + 2 = cosh x

Evaluate Cosh^-1 (0.867)

Asked by jonh