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An observer on a cliff 1000 dm above sea level sights two ships due east. the angles of depression of the ships are 44o and 32o. Find the distance between the ships.
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Answered by
Steve
draw a diagram. If the near ship is at distance x from shore, and the ships are d apart, then
x = 1000 cot44°
x+d = 1000 cot32°
so, d = 1000(cot32°- cot44°)
x = 1000 cot44°
x+d = 1000 cot32°
so, d = 1000(cot32°- cot44°)
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