Asked by jonh
f=8arctan(6x)
f'=
f'=
Answers
Answered by
Steve
d/dx (arctan u) = 1/(1+u^2) du/dx, so
f' = 8/(1+(6x)^2) * 6 = 48/(1+36x^2)
f' = 8/(1+(6x)^2) * 6 = 48/(1+36x^2)
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