Asked by Cristian
When two objects move uniformly toward each other, they get 3.0 m closer each second, and when they move uniformly in the same direction with their original speeds, they get 1.0 m closer each 17 seconds. What is the speed (in meters/second) of the faster moving object?
Answers
Answered by
drwls
Let V1 be the higher speed and V2 the lower
V1 + V2 = 3.0 m/s
V1 - V2 = 1/17 m/s = 0.0588 m/s
2V1 = 3.0588 m/s
V1 = 1.529 m/s
V2 = 1.471 m/s
V1 + V2 = 3.0 m/s
V1 - V2 = 1/17 m/s = 0.0588 m/s
2V1 = 3.0588 m/s
V1 = 1.529 m/s
V2 = 1.471 m/s