Asked by Hafzah
                What is the shortest distance from the point (2,1) to the line x-y= -1
            
            
        Answers
                    Answered by
            Reiny
            
    given a point (a,b) not on the line, the distance from that point to Ax + By + C = 0  is
|aA + bB + C|/(√(A^2+B^2)
so distance
= |2(1) + 1(-1) + 1 |/√(1+1)
= 2/√2 or after rationalizing, = √2
    
|aA + bB + C|/(√(A^2+B^2)
so distance
= |2(1) + 1(-1) + 1 |/√(1+1)
= 2/√2 or after rationalizing, = √2
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