Asked by lee

what is an equation of a parobola with the given vertex and focus?
vertex(5,4) and focus(8,4)
Can someone show me the steps to get the equation please?

Answers

Answered by Steve
the parabola with vertex (0,0) and focus (p,0) is

4px = y^2

We need to shift the vertex to (5,4), so substitute

4p(x-5) = (y-4)^2

The focus is 3 units away from the vertex, so p=3, and we have

12(x-5) = (y-4)^2
Answered by lee
So x=1/12(y-4)^2+5 would be the answer?
Answered by Imposter
C
D
C
B
A
100% Parabolas Unit 7 Lesson 2
Answered by Countess Nightmare
1.) focus: (0,3) ; directrix: y = -3
2.) x=-1/19^y^2
3.) y=1/8x^2
4.) vertex (3,3); focus (3,6); directrix y= 0
5.) 1/12 (y-4)^2+5
Answered by DemonSlayer
Countess Nightmare and Imposter are 100% correct! Thankssss!
Answered by Sheesh
Correct ^
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