Asked by lee
what is an equation of a parobola with the given vertex and focus?
vertex(5,4) and focus(8,4)
Can someone show me the steps to get the equation please?
vertex(5,4) and focus(8,4)
Can someone show me the steps to get the equation please?
Answers
Answered by
Steve
the parabola with vertex (0,0) and focus (p,0) is
4px = y^2
We need to shift the vertex to (5,4), so substitute
4p(x-5) = (y-4)^2
The focus is 3 units away from the vertex, so p=3, and we have
12(x-5) = (y-4)^2
4px = y^2
We need to shift the vertex to (5,4), so substitute
4p(x-5) = (y-4)^2
The focus is 3 units away from the vertex, so p=3, and we have
12(x-5) = (y-4)^2
Answered by
lee
So x=1/12(y-4)^2+5 would be the answer?
Answered by
Imposter
C
D
C
B
A
100% Parabolas Unit 7 Lesson 2
D
C
B
A
100% Parabolas Unit 7 Lesson 2
Answered by
Countess Nightmare
1.) focus: (0,3) ; directrix: y = -3
2.) x=-1/19^y^2
3.) y=1/8x^2
4.) vertex (3,3); focus (3,6); directrix y= 0
5.) 1/12 (y-4)^2+5
2.) x=-1/19^y^2
3.) y=1/8x^2
4.) vertex (3,3); focus (3,6); directrix y= 0
5.) 1/12 (y-4)^2+5
Answered by
DemonSlayer
Countess Nightmare and Imposter are 100% correct! Thankssss!
Answered by
Sheesh
Correct ^
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