Asked by allen

Your question: "The shorter diagonal of a rhombus is 50 mm long. Each of its obtuse angles measures 140. Find the length of each side."

12 years ago

Answered by bobpursley

Then each of the acute angles is 40, and the the angle bisected by the shorter diagonol divides into two 70deg

law of sines:
50mm/Sin40= s/Sne70

12 years ago

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