Asked by Anonymous

Rearrange this expression into quadratic form, ax2 bx c = 0

.2= ((x^2)/(55-x))

where a = 1, and identify the values of b and c.

Answers

Answered by Steve
.2(55-x) = x^2
11 - x/5 = x^2

x^2 + 1/5 x - 11 = 0
Answered by Ali
a. 1
b. 0.2
c. -11
Answered by Mikey
a=1
b=0.20
c=-3

0.20 = x^2/(15-x)
((15-x))0.20 = (x^2/(15-x))((15-x))
(15-x)0.20 = x^2
(-3)3-0.20x = x^2(-3)
(+0.20x)-0.20x = x^2-3(+0.20x)
0 = 1x^2+0.20x-3
Answered by Anonymous
0.20=π‘₯^/35βˆ’π‘₯
Answered by Anonymous
0.20=π‘₯^2/35βˆ’π‘₯
Answered by Godzilla
A=1, B=0.2, C=-17
It’s the right answer
Answered by Marisa
A= 1, B= 0.2, C= -13
Answered by Jasmine chalico
1)Γ—(Γ—+5)=2
Ans
Γ—Β²+5Γ—-2=0
Step by step
Γ—Β²+5Γ—=2
Γ—Β²+5Γ—-2=0
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