Asked by Marcus
Which of the following solutes in aqueous solution would be expected to exhibit the smallest freezing-point lowering (assuming ideal behavior?
0.1 m NaCl
.2 m CH3COOH
.05 m Al2(SO4)3
.1 m MgCl2
.25 m NH3
What would be the steps to picking the right option? Because just picking .05 because it appears to be the smallest amount is likely wrong.
0.1 m NaCl
.2 m CH3COOH
.05 m Al2(SO4)3
.1 m MgCl2
.25 m NH3
What would be the steps to picking the right option? Because just picking .05 because it appears to be the smallest amount is likely wrong.
Answers
Answered by
DrBob222
delta T = i*Kf*m
Since Kf is constant we can forget that. dT depends upon i and m so
i*m for each.
NaCl is 0.1*2 = ? for i = 2
CH3COOH is 0.2*1 for i = 1
Al2(SO4)3 is 0.05*5 for i = 5
MgCl2 i = 3
NH3 i = 1
The greatest i*m causes the greatest dT (or the smallest i*m causes the least dT).
Since Kf is constant we can forget that. dT depends upon i and m so
i*m for each.
NaCl is 0.1*2 = ? for i = 2
CH3COOH is 0.2*1 for i = 1
Al2(SO4)3 is 0.05*5 for i = 5
MgCl2 i = 3
NH3 i = 1
The greatest i*m causes the greatest dT (or the smallest i*m causes the least dT).
Answered by
John
It’s nacl
Answered by
Kate
0.1 m MgCl2
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