Asked by Maria
CH4(g) + 2O2(g) = CO2(g) + 2H20(g). What volume of O2 is required to react with 2.0 mol CH4 at 50 degrees Celsius and .500 atm?
Answers
Answered by
DrBob222
At STP volume oxygen is
volume O2 = 2.0 mol CH4 x (2 mols O2/1 mol CH4) = 2*2/1 = 4 mols O2.
Use PV = nRT to convert to L at the conditions of the problem.
volume O2 = 2.0 mol CH4 x (2 mols O2/1 mol CH4) = 2*2/1 = 4 mols O2.
Use PV = nRT to convert to L at the conditions of the problem.
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