Asked by Anonymous
                How many milliliters of pure acid must be added to 150 milliliters of a 70% solution of acid to obtain a 80% solution?
            
            
        Answers
                    Answered by
            Reiny
            
    let the amount to be added be x ml
.7(150) + x = .8(150+x)
times 10
7(150) + 10x = 8(150+x)
solve for x
    
.7(150) + x = .8(150+x)
times 10
7(150) + 10x = 8(150+x)
solve for x
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