Asked by Anonymous
A battery delivering a current of 55.0 A to a circuit has a terminal voltage of 21.8 V. The electric power being dissipated by the internal resistance of the battery is 36 W. Find the emf of the battery.
Answers
Answered by
Henry
Vi * I = 36 W.
Vi * 55 = 36
Vi = 0.655 V0lts. = Internal voltage drop.
E = 21.8 + 0.655 = 22.5 V. = emf of battery.
Vi * 55 = 36
Vi = 0.655 V0lts. = Internal voltage drop.
E = 21.8 + 0.655 = 22.5 V. = emf of battery.
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