Question
A battery delivering a current of 55.0 A to a circuit has a terminal voltage of 21.8 V. The electric power being dissipated by the internal resistance of the battery is 36 W. Find the emf of the battery.
Answers
Henry
Vi * I = 36 W.
Vi * 55 = 36
Vi = 0.655 V0lts. = Internal voltage drop.
E = 21.8 + 0.655 = 22.5 V. = emf of battery.
Vi * 55 = 36
Vi = 0.655 V0lts. = Internal voltage drop.
E = 21.8 + 0.655 = 22.5 V. = emf of battery.