Asked by Lily
                How can I find the area of a square?
            
            
        Answers
                    Answered by
            Ms. Sue
            
    Check this interactive site.
http://www.mathopenref.com/squarearea.html
    
http://www.mathopenref.com/squarearea.html
                    Answered by
            Lily
            
    how about a rectangle?
    
                    Answered by
            Ms. Sue
            
    http://www.mathopenref.com/rectanglearea.html
    
                    Answered by
            Lily
            
    Thank you so much. I have another question :) In my Pre Algebra book, I have a question like this:
Draw a line from one vertex to a point on another side to create a triangle. Cut along the line.
What do they exactly mean by 'cut along the line'?
    
Draw a line from one vertex to a point on another side to create a triangle. Cut along the line.
What do they exactly mean by 'cut along the line'?
                    Answered by
            Ms. Sue
            
    I believe it means to use a pair of scissors and cut on the line you've just drawn from the vertex (corner) to a point on the other side to make a triangle.
    
                    Answered by
            Lily
            
    oh ok, thank you very much! Also, when finding the area of a shape, the formula is A= bh. But my question is, when you have two different units like w=2ft and h=2yd, which one do I have to choose? Just any of the two?
    
                    Answered by
            Ms. Sue
            
    You can choose either -- but then you must convert the other to the unit you choose.
For instance, for w = 2 ft. and h = 2 yd., I'd choose feet as the unit.
2 yd. = 6 feet.
w = 2 ft. h = 6 ft.
    
For instance, for w = 2 ft. and h = 2 yd., I'd choose feet as the unit.
2 yd. = 6 feet.
w = 2 ft. h = 6 ft.
                    Answered by
            Lily
            
    So 1yd would be equal to 3ft? 
    
                    Answered by
            Ms. Sue
            
    That's right.  :-)
    
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