A= 4πr² =>
r=sqrt(A/4π )= sqrt(1.2/4•3.14)= 0.31 m
φ=q/4πε₀r =>
q= 4πε₀rφ=
=4π•8.85•10⁻¹²•0.31•590=2.03•10⁻⁸ C
An equipotential surface that surrounds a point charge q has a potential of 590 V and an area of 1.20 m2. Determine q.
2 answers
I’m stupid