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Assuming that 9.0\% of the energy output of a 65W lightbulb is visible light and that the average wavelength of the light is 550 {\rm nm}, how many photons are emitted by the lightbulb each second?
12 years ago

Answers

bobpursley
Number photons*energy each=.09(65)

energy each=hf=h*c/lambda

12 years ago

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