Assume that Kc = 0.0360 at 520°C for the first reaction above. What is the Kc for the second reaction at the same temperature?

Question

2 HI(g)-> H2(g) + I2(g)


H2(g) + I2(g) -> 2 HI(g)

I thought the answer woudl just be negative because all you have to do is switch the products and reactants but its wrong

Answer 1

then like the same for thsi one

Assume that Kc = 0.0130 at 520°C for the first reaction above. What is the Kc for the second reaction at the same temperature?

2 HI(g)->H2(g) + I2(g)

HI(g)->½ H2(g) + ½ I2(g)

why cant you just divide the k by 2?

Answer 2

nevermind i got it

Answer 3

Just to make sure.
K for the reverse direction is 1/K.

K for the 1/2 reaction is sqrt K.