Asked by Paula
A rock is thrown upward with a velocity of 15 meters per second from the top of a 26 meter high cliff ad i misses the cliff on the way back down. when will the rock be 5 meters from the water below?
Answers
Answered by
Reiny
height = -4.9t^2 + 15t + 26
When the rock is 5 metres above the water,
5 = -4.9t^2 + 15t + 26
4.9t^2 - 15t - 21 = 0
t = (15 ± √636.6)/9.8
= 4.1052 seconds or a negative
After appr 4.1 seconds, the rock is 5 metres above the water.
When the rock is 5 metres above the water,
5 = -4.9t^2 + 15t + 26
4.9t^2 - 15t - 21 = 0
t = (15 ± √636.6)/9.8
= 4.1052 seconds or a negative
After appr 4.1 seconds, the rock is 5 metres above the water.
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