A brewery's filling machine is adjusted to fill bottles with a mean of 32.6 oz. of ale and a variance of 0.004. Periodically, a bottle is checked and the amount of ale noted.
(a) Assuming the amount of fill is normally distributed, what is the probability that the next randomly checked bottle contains more than 32.68 oz? (Give your answer correct to four decimal places.)
(b) Let's say you buy 97 bottles of this ale for a party. How many bottles would you expect to find containing more than 32.68 oz. of ale? (Round your answer up to the nearest whole number.)
how many bottles?
3 answers
#1 and #3 in Related Questions... answers YOU have received on this same subject, will provide the formulas and methods.
Oops I thought you were Anonymous.. :P
a. Z = (score-mean)/SD
Variance = SD^2
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability related to the Z score.
b. Multiply answer in a by 97.
Variance = SD^2
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability related to the Z score.
b. Multiply answer in a by 97.
1 answer