Asked by Ericca
Joanne drives her car with a mass of 1000 {\rm kg} at a speed of 23m/s .
Find a road friction force that is need to bring her car to a halt in 14s .
Find a road friction force that is need to bring her car to a halt in 14s .
Answers
Answered by
Henry
V = Vo + a*t.
a = (V-Vo)/t = (0-23)/14 = -1.64 m/s^2.
F = m*a = 1000*(-1.64) = -1640 N.
The negative sign means that the force
is opposing vehicle movement.
a = (V-Vo)/t = (0-23)/14 = -1.64 m/s^2.
F = m*a = 1000*(-1.64) = -1640 N.
The negative sign means that the force
is opposing vehicle movement.
There are no AI answers yet. The ability to request AI answers is coming soon!