Asked by Aaron M

I have to find the exact value(so in fraction form.. like 1231231/41231 or something) of a^4b^2/c^2 , a = (2/5)^2, b = (8/5)^5 c= (4/5)^10 I'm honestly not sure how to get around to doing it with working
Answered by Wobb
LCD: 3 * 4 * 11 * 7 = 924

so...

2/3 = 2(308)/924 = 616/924

3/4 = 3(231)/924 = 693/924

2/11 = 2(84)/924 = 168/924

5/21 = 5(44)/924 = 220/924

if you can't get the answer from those, then go to your teacher for help...immediately !!

one problem at a time.

@ƒ

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Answered by Steve
a^4b^2/c^2 , a = (2/5)^2, b = (8/5)^5 c= (4/5)^10

a^4 = (2/5)^8 = 2^8/5^8
b^2 = (8/5)^10 = 2^30/5^10
c^2 = (4/5)^20 = 2^40/5^20

a^2b/c = 2^(8+30-40)/5^(8+10-20) = 2^-2/5^-2 = 5^2/2^2 = 25/4
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