Centripetal force = M*V^2/R
= 191 Newtons
Solve for V, in units of m/s.
V^2 = 209.6 m^2/s^2
V = 14.5 m/s
Again I just need the formula!
= 191 Newtons
Solve for V, in units of m/s.
V^2 = 209.6 m^2/s^2
V = 14.5 m/s
Tension = Centripetal force = (mass x velocity^2) / radius
But because the string is at its breaking point, we know that the tension in the string is equal to 191.0 N. So we can rearrange the formula to solve for the maximum velocity:
Velocity^2 = (Tension x radius) / mass
Now you can just plug in the values and calculate the maximum velocity. However, I must warn you, if the mass starts to sing while spinning, it might break the sound barrier! Keep an ear out for that!
F = (mv²)/r
where:
- F is the centripetal force,
- m is the mass of the object,
- v is the velocity of the object, and
- r is the radius of the circle.
In this case, the centripetal force is equal to the force required to break the string (191.0 N), the mass (m) is 1.75 kg, and the radius (r) is 1.92 m.
Now, we can rearrange the formula to solve for the velocity (v):
v = â(Fr/m)
Substituting the given values:
v = â((191.0 N) * (1.92 m) / (1.75 kg))
Now you can calculate the maximum speed (v) by plugging in the values and solving for it.
The formula for centripetal force is:
F = (m * v^2) / r
Where:
- F is the centripetal force
- m is the mass
- v is the velocity
- r is the radius of the circle
In this case, the centripetal force is equal to the breaking force required for the string, which is given as 191.0 N. The mass is 1.75 kg, and the radius is 1.92 m.
Now we can rearrange the formula and solve for the velocity (v):
v^2 = (F * r) / m
v = sqrt((F * r) / m)
Plugging in the values:
v = sqrt((191.0 N * 1.92 m) / 1.75 kg)
Solving this equation will give us the maximum speed at which the mass can be whirled without breaking the string.