Asked by Annette
How many moles of Al(OH) are required to completely react with 2.75mol of H2SO4?
Answers
Answered by
bobpursley
In what reaction? This one?
Al(OH)3+ 3H2SO4 >>Al2(SO4)3 + 3H2O
you need 1/3 the moles, or 2.75/3 moles of aluminum hydroxide.
Al(OH)3+ 3H2SO4 >>Al2(SO4)3 + 3H2O
you need 1/3 the moles, or 2.75/3 moles of aluminum hydroxide.
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