Question

Find the equation of the parabola through (-15/4 ,2) and (0,-1) whose axis is parallel to the x-axis and the latus rectum equal to 4
(y-3)SQUARE = 4(X+4) AND
(Y+2)SQUARE = -4(X-1/4)
Graph the parabola x = 2y^2+8y+11. Find the vertex , an equation of the axis, the focus, and the endpoints of the latus rectum

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