Asked by Anonymous
What is the first derivative of
L(x) = ((4+x^2)^0.5) + ((25 + (10-x)^2)^0.5)
L(x) = ((4+x^2)^0.5) + ((25 + (10-x)^2)^0.5)
Answers
Answered by
Reiny
L ' (x) = (1/2)(4 + x^2)^(-1/2) (2x) + (1/2)(25 + (10-x)^2 )^(-1/2) ( 2(10-x)(-1) )
I will let you simplify it a bit.
I will let you simplify it a bit.
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