an aqueous solution contains 1 mol of S2O3 ions and this reduces 4 mol chlorine molecules.What is the sulphur containing product of this reaction?

Answer 1

Cl2 + 2e = 2Cl^-\
2S2O3^2- ==> S4O6^2- + 2e
S2O3^2- is thiosufate.
S4O6^2- is tetrathionate.