Question

A particle revolves in a horizontal circle of radius 3.20 m. At a particular instant, its
acceleration is 1.20 m/s
2
in a direction that makes an angle of 55.0º to its direction of motion.
Determine its speed (a) at this moment, and (b) 1.50 s later, assuming constant magnitude of
tangential acceleration.

Answer 1

I am not certain how the 55 degrees is measured? Is it in the plane of revolution? towards inside, or outside?

Answer 2

55 from the tangent, so i think its accelerating.

Answer 3

Centripetal acceleration equals tangent 55 times 1.05. Obtain the velocity at that point with that. V=Vinitial+at, where a is the anet in the direction of motion. Therefore, get the original velocity, find the anet through a cosine with the tangent acceleration, and solve the kinematics equation.