Asked by kylie
Ethylene glycol (antifreeze) has a density of 1.11 {\rm g/cm^3}.What is the mass in G of 435mL of this liquid?
Answers
Answered by
Steve
mass = density (g/mL) * volume (mL), so
1.11g/cm^3 * 435cm^3 = 482.85 g
1.11g/cm^3 * 435cm^3 = 482.85 g
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