Asked by Anonymous
Name the diameter, radius, center, and the equation of the circle with a diameter that has endpoints at (-3, 4) and (5, -2).
Answers
Answered by
Steve
the center is at the midpoint of diameter: (1,1)
radius = 1/2 √(8^2+6^2) = 5
(x-1)^2 + (y-1)^2 = 25
radius = 1/2 √(8^2+6^2) = 5
(x-1)^2 + (y-1)^2 = 25
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