Asked by kexy

a car starts from rest at constant acceleration of 2m/s2 at the same instant, a truck travelling at a constant speed of 10m/s overtakes and passes the car
i) how far beyond the starting point will the car overtake the truck
ii) after what time will this happen
iii) at what instant will be the speed of the car
Answered by bobpursley
They both travel the same distance, in the same time.

truck:
distance=10t
car:
distance=1/2 2 t^2

10t=t^2
10=t so time is ten seconds.
distance=10*t

velocitycar=2*t=20m/s
Answered by Anonymous
2.5m/s

Answered by anonymous
the answer is 20m/s
Answered by Umesh
Good
Answered by Sarita
Equation of motion for he truck: s=ut

Equation of motion for the car: s=1/2at^2

the second solution gives , s=2u^2/a = 2*10^2/2 = 100m
Answered by Lena
180 m from stoplight at t=12 s
Answered by Joel
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Answered by David
Full calculation
Answered by David
Full calculation of the problem
Answered by Joel
Want all answers step by step working outs
Answered by Graffy
1 want working out for the answer
Answered by Junior
Solving the problem stap by stap calculation please?
Answered by Visiion Kipandu
Please show step by step
Answered by Gerry
Please show all calculations step by step
Answered by Habtamu Tadesse
thats good✍️
Answered by Anonymous
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