Asked by Anonymous
Median family income in country x between 1990 and 1999 can be modeled by f(x)=1144.7(x-1990)+35,834 where x is the year. Determine the median income was $42,303.
I did it this way don't know if it's right
f(x)=1144.7(x-1990)+35,834
42,303-35,834 = 1144.7 - (x-1990) + 35,834
6469. 1144 7 - (x-1990). 35,834
.177=x-1990
The median income was $1144.7 every year
Thanks for all your help:-)
I did it this way don't know if it's right
f(x)=1144.7(x-1990)+35,834
42,303-35,834 = 1144.7 - (x-1990) + 35,834
6469. 1144 7 - (x-1990). 35,834
.177=x-1990
The median income was $1144.7 every year
Thanks for all your help:-)
Answers
Answered by
Henry
F(x) = 1144.7(x-1990) + 35,834 = $42303.
1144.7x for y - 2277953 + 35834 = 42303
1144.7x - 2242119 = 42303
1144.7x = 2284422
X = 1995.65 or 1996.
The Median income was $42,303 for year
1996.
1144.7x for y - 2277953 + 35834 = 42303
1144.7x - 2242119 = 42303
1144.7x = 2284422
X = 1995.65 or 1996.
The Median income was $42,303 for year
1996.
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