Asked by J
Hi I need help with this one problem. It's on page 167 algebra with pizzazz. It has to use the addition method.
3x-5y=7
5x-2y=-1
3x-5y=7
5x-2y=-1
Answers
Answered by
J
How do you start it then I can solve it easily. I'm not cheating.!!!!!
Answered by
Reiny
You want either the x's or the y's to have opposite coefficients.
let's work on the y's
#1 times 2 ----> 6x - 10y = 14
#2 times -5 ---> -25x + 10y =5
add them:
-19x = 19
x = -19/19 = -1
back in #1:
3(-1) - 5y = 7
=5y = 7 + 3 = 10
y = -2
x = -1 , y = -2
let's work on the y's
#1 times 2 ----> 6x - 10y = 14
#2 times -5 ---> -25x + 10y =5
add them:
-19x = 19
x = -19/19 = -1
back in #1:
3(-1) - 5y = 7
=5y = 7 + 3 = 10
y = -2
x = -1 , y = -2
Answered by
Anonymous
answers...
Answered by
Anonymous
i don't know im... im cheating ...this shiz is hard
Answered by
a
I like turtles
Answered by
rdwn
3x-5y=7 and 5x-2y=-1
Answered by
rdwn
Hi I need help with this one problem. It's on page 167 algebra with pizzazz. It has to use the addition method.
3x-5y=7
5x-2y=-1
3x-5y=7
5x-2y=-1
Answered by
brittany
-1,-2
Answered by
Anonymous
x<-4
Answered by
stormy
(-1,-2)
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