Asked by don
the lines satisfying the equations x+2y=3 and 3y+ax=2 are perpendicular to each other. find the value of 'a'. please answer and explain how you got, please!!
Answers
Answered by
Reiny
slope of first line = -1/2
slope of 2nd line = -a/3
to be perpendicular, they must be negative reciprocals of each other, or, when multiplied we should get -1
(-1/2)(-a/3) = -1
a/6 = -1
a = -6
slope of 2nd line = -a/3
to be perpendicular, they must be negative reciprocals of each other, or, when multiplied we should get -1
(-1/2)(-a/3) = -1
a/6 = -1
a = -6
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