Asked by Anonymous

A bag contains 4 red and 3 black balls. A second bag contains 2 red and 4 black balls. One bag is selected at random. From the selected bag, one ball is drawn. Find the probability that the drawn ball is red.

Answers

Answered by Reiny
consider the result as 2 independent events

bag1, red
bag2, red

Prob(bag1,red) = (1/2)(4,7) = 2/7
prob(bag2,red) = (1/2)2/6) = 1/6

prob(your event) = 2/7 + 1/6 = 19/42
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