Question
1/tan beta +tan beta=sec^2 beta/tan beta
Answers
Steve
1/tanβ + tanβ
(1+tan^2 β)/tanβ
sec^2 β/tan
since sec^2 β = 1+tan^2 β
(1+tan^2 β)/tanβ
sec^2 β/tan
since sec^2 β = 1+tan^2 β