Asked by saki
1/tan beta +tan beta=sec^2 beta/tan beta
Answers
Answered by
Steve
1/tanβ + tanβ
(1+tan^2 β)/tanβ
sec^2 β/tan
since sec^2 β = 1+tan^2 β
(1+tan^2 β)/tanβ
sec^2 β/tan
since sec^2 β = 1+tan^2 β
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