assume that 13.5g of AL react with HCl according to the following equation, at STP: Al(s) + HCl(aq) ---> AlCl3 + H2(g) Remember to balance the equation first.

So many concepts here. What is it you don't understand?

everything my teacher didn't teach us

C'mon. Get serious. If I don't know what you don't understand about this I can't help you. To start can you balance the equation? If so do so. If not why can't you. Go from there with the next thing you don't understand.

actually i just need c

In the future, if you will show what you can do and work through that, then ask your question, all of this preliminary stuff is not necessary.

Remember that a mole of any (ideal) gas will occupy 22.4 L at STP.
L H2 @ STP = mols H2 x 22.4 L/mol = ?.

how do yu se up the equation for this Q.??

You didn't ask a question.

I don't understand it either!!!

.500g

A.500

B.750
C.16.8