Asked by jason

While on vacation, Kevin went for a swim in a nearby lake. Swimming against the current, it took him 8 minutes to swim 200 meters. Swimming back to shore with the current took half as long. Find Kevin's average swimming speed and the speed of the lake's cuurent.
Answered by Reiny
Let the speed of the current be y m/min
let Kevin's rate of swimming be x m/min

against the current: 8(x-y) = 200
with the current : 4(x+y) = 200

from the first 8x - 8y = 200 reduced to
x-y = 25

from the second equation x + y = 50

add them: 2x = 75
x = 37.5 m/min

subbing back in the second
y = 12.5

So the lake's current was 12.5 m/min
and his rate of swimming in still water would be 37.5 m/min
Answered by cheyenne
I NEED HELP IN CONVERTING 33/50 INTO A DECIMAL
Answered by Ms. Sue
Cheyenne -- please click <u>Post a New Question</u> and ask ask your question.
Answered by yo
yoyoyo
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