Asked by glindyll
A worker can supply a maximum pull of 150 lbs. on a cart which has a handle set an angle of 40degree above the horizontal. what is the coefficient of friction if he can just move a total load of 1500lbs. ?
Answers
Answered by
drwls
Normal force at maximum moveable load
= 1500 - 150sin40 = 1404 lb
Coefficient of friction (static)
= (tangential force)/(normal force)
= 1500 cos40/1404 = 0.818
= 1500 - 150sin40 = 1404 lb
Coefficient of friction (static)
= (tangential force)/(normal force)
= 1500 cos40/1404 = 0.818
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