Final kinetic energy = (1/2)M*Vfinal^2
= 1.715*10^5 J
Work against resistance force
= (Force)*Vaverage*time
= 402.5*(17.5/2)(18.8)
= 6.62*10^4 J
Total work done = 2.38*10^5 J
Average power = (Work)/(Time) = 1.26*10^4 W
a car with amass of 1120 kg starts from rest and accelerates to the speed of 17.5 m/s in 18.8 s. assume that the force of resistance remains constant at 402.5 N during this time.
what is the average power developed by the car's engine?
answer in units of W
can you please explain how you got the answer as well?!?!?!?!?!
PLEASE AND THANK YOU
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