Asked by Thad


MIke and Shayne reacted sodium chloride with silver nitrate as indicated in the reaction below:
AgNO3(aq) + NaCl(aq) → AgCl (s) + NaNO3 (aq)
The actual yield of their silver chloride was 0.365 g. According to their calculations, they should have theoretically obtained 0.516 g. What was their percent yield?
Answered by DrBob222
%yield = (actual yield/theor yield)*100
= ?
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