Question
sodium metal dissolves im liquid mercury to form of NA(s) and Hg(l) are 0.97 g/ml and 13.6 g/ml respectively. a sodium amalgoum is made by dissolving 10 ml Na (s) in 20.0 ml Hg (l). The final volume of solution is 21.0 ml. Calculate the molarity of Na in the solution.
Answers
Convert volume Na to grams using density, then convert to mol. mol = grams/molar mass.
M Na = mols Na/total volume in L.
M Na = mols Na/total volume in L.
Related Questions
I need help classifying these as physical and chemical properties!
1. sodium metal in chlorine ga...
sodium metal dissolves in liquid mercury to form a solution called a sodium amalgam. the densities o...
Sodium metal dissolves in liquid mercury to form a solution called a sodium amalgam. The densities o...