Question

CH3CH2CHO + 2Ag(NH3)2OH = CH3CH2COONH4+2Ag+H20+3NH3

yield of Ag obtained = 75%
calculate minimum mass of propanal that must have been used to form 5g of silver

Answer 1

looks like each mole of propanol produces 2 moles of Ag.

If the reaction yields 75%, then each mole of propanol produces 1.5 moles Ag.

So, how many moles of Ag in 5g?

3/2 that of propanol, convert to g.

Answer 2

still confused

Answer 3

1 mole of Ag = 108 g
So, 5g = 5/108 = 0.0463 moles Ag

Each mole of propanol produces 1.5 moles Ag, so each mole of Ag requires 2/3 moles of propanol (sorry for the 3/2 typo above).

2/3 * .0463 = 0.0309 moles of propanol required.

mol wt of propanol is 58g, so you need 1.79 g

Answer 4

thankyou i appreciate it

Answer 5

thankyou i appreciate it

could u however plz explain how u knew 1 mol of ag =108g

Answer 6

never mind i know now thankyou