Asked by adam
the largest value of n for which 10^n evenly divides 2^9*15^2*35 is a)2 b)3 c)4 d)5 e)6
Answers
Answered by
Reiny
10^n = 2^n * 5^n
thus no matter what n is, 10^ contains only the factors 2 and 5
but our divisor is
2^9 * 15^2 * 35
= 2^9 * 3^2 * 5^2 * 5 * 7
which contains factors of 3 and 7
so no matter what n is , 10^n does NOT divide by your given number.
thus no matter what n is, 10^ contains only the factors 2 and 5
but our divisor is
2^9 * 15^2 * 35
= 2^9 * 3^2 * 5^2 * 5 * 7
which contains factors of 3 and 7
so no matter what n is , 10^n does NOT divide by your given number.