On Mars, the acceleration due to gravity is 3.71 m/s2. How far would a rock fall in 3 s if you dropped it on Mars?

Answer 1

Knowns:
acceleration (a): -3.71 m/s^2
time (t): 3 sec
initial velocity (Vi): 0 m/s
*Since you dropped it, there is no force put into making the ball fall. That's why the initial velocity is 0.

Unknown:
Fall distance(Δy):?

Δy=Vit+(1/2)at^2
Δy=0+(1/2)(-3.71)(3)^2
Δy=-16.695m

The ball would fall 16.695m