If secx = -3, and x lies in quadrant II find tan x/2

Question

-√2 or √3/3?

Answer 1

sec x = -3 ---> cosx = -1/3
sinx = 2√2/3 , in II the sine is + , and I used Pythagoras

tan x/2= sinx/2 / cos x/2

Now look how I answered your second question in
http://www.jiskha.com/display.cgi?id=1359587430

This one is very similar to it
give it a shot

btw, my answer was +√2

(since x was in the second quadrant, x/2 must be in the first, where everything is positive. So -√2 would be wrong without even doing any calculations)

Answer 2

Okay I think I sort of understand it now. Thank you so much, I really appreciate it