Question
How many moles of Ca(OH)2 are produced when 9.19 grams of CaH2 and 7.90 grams of H2O react ?
Answers
Devron
The reaction is as followed:
CaH2 +2H2O------> Ca(OH)2 +2H2
9.19 g of CaH2/42.1 g of CaH2 *mol-1= moles of CaH2
7.90 g of H20/18g of H20 *mol-1=moles of H20
CaH2 is the limiting reagent.
moles of CaH2=moles of Ca(OH)2
moles of Ca(OH)2 *molecular mass of Ca(OH)2= mass of Ca(OH)2 in g.
CaH2 +2H2O------> Ca(OH)2 +2H2
9.19 g of CaH2/42.1 g of CaH2 *mol-1= moles of CaH2
7.90 g of H20/18g of H20 *mol-1=moles of H20
CaH2 is the limiting reagent.
moles of CaH2=moles of Ca(OH)2
moles of Ca(OH)2 *molecular mass of Ca(OH)2= mass of Ca(OH)2 in g.