Question

An atomic particle moves in a linear motion according to the formula s = 19 - 14t2 + 4t3. Determine the particle's velocity at the end of 2.9 seconds.

velocity in m/s =

My Answer

S'= 0-28t+12t^2
S'(2.9) = 0-28(2.9)+12(
2.9)^2
= 0-81.2+100.92
=19.72

Can you please confirm this answer


velocity in m/s = 19.72

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